The radius of the circle passing through the foci of the ellipse $\frac{x^2}{16} + \frac{y^2}{9} = 1$ and having its centre at $(0, 3)$ is:
Step-by-Step Solution
Key Concept: $a^2 = 16$, $b^2 = 9$, $c = \sqrt{7}$. Foci: $(\pm \sqrt{7}, 0)$. Radius from $(0, 3)$ to $(\sqrt{7}, 0)$: $r = \sqrt{7 + 9} = 4$.
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Correct Answer: (1)