Sets, Relations & Functions
General
Grade 11
Question:
<p>Let <span class="math-inline">\(f(x)=x+3\)</span> for <span class="math-inline">\(x\in\mathbb{Q}\)</span>, <span class="math-inline">\(4x\)</span> for <span class="math-inline">\(x\in\mathbb{R}\setminus\mathbb{Q}\)</span>; and <span class="math-inline">\(g(x)=\sqrt{5}+x\)</span> for <span class="math-inline">\(x\in\mathbb{R}\setminus\mathbb{Q}\)</span>, <span class="math-inline">\(-x\)</span> for <span class="math-inline">\(x\in\mathbb{Q}\)</span>. Find the nature of <span class="math-inline">\((f-g)(x)\)</span>.</p>
One-one and onto
One-one into
Onto but not one-one
<strong>Neither one-one nor onto</strong>
Step-by-Step Solution
Key Concept: General
<div class="solution"><p><strong>Key Idea:</strong> Write <span class="math-inline">\((f-g)(x)\)</span> on rational and irrational branches separately, then check cross-branch collisions.</p><p><strong>Step 1:</strong> <span class="math-inline">\(x\in\mathbb{Q}\)</span>: <span class="math-inline">\((f-g)(x) = 2x+3\)</span></p><p><strong>Step 2:</strong> <span class="math-inline">\(x\in\mathbb{R}\setminus\mathbb{Q}\)</span>: <span class="math-inline">\((f-g)(x) = 3x-\sqrt{5}\)</span></p><p><strong>Step 3:</strong> Not one-one — a rational output can equal an irrational-branch output (cross-branch collision exists).</p><p><strong>Step 4:</strong> Not onto — certain irrationals cannot be achieved from either branch simultaneously.</p><p><strong>Answer: Neither one-one nor onto</strong></p><div class="trap-box"><strong>Trap:</strong> Each branch may look injective individually, but cross-branch collisions destroy one-one behaviour.</div><div class="key-concept"><strong>Key Concept:</strong> Rational/irrational piecewise functions — test rational∩irrational image overlap</div></div>
Correct Answer: 4