Sets, Relations & Functions
General
Grade 11
Question:
<p>If <span class="math-inline">\(f:[\frac{7}{2},\infty)\to[-\frac{9}{4},\infty)\)</span>, <span class="math-inline">\(f(x)=x^2-7x+10\)</span>, find <span class="math-inline">\(f^{-1}(x)\)</span>.</p>
Step-by-Step Solution
Key Concept: General
<div class="solution"><p><strong>Key Idea:</strong> Complete the square. Domain <span class="math-inline">$x\ge\frac{7}{2}$</span> tells which root to keep.</p><p><strong>Step 1:</strong> <span class="math-inline">$y = (x-\frac{7}{2})^2 - \frac{9}{4}$</span></p><p><strong>Step 2:</strong> <span class="math-inline">$x-\frac{7}{2} = +\sqrt{y+\frac{9}{4}}$</span> (positive, since <span class="math-inline">$x\ge\frac{7}{2}$</span>)</p><p><strong>Step 3:</strong> <span class="math-block">$$f^{-1}(x) = \frac{7+\sqrt{9+4x}}{2}$$</span></p><div class="trap-box"><strong>Trap:</strong> If you keep both ± signs, the inverse is not a function. The domain restriction removes one branch.</div><div class="key-concept"><strong>Key Concept:</strong> Inverse of restricted parabola — domain decides which square-root branch survives</div></div>
Correct Answer: (7 + √(9+4x))/2