Hyperbola
Eccentricity
JEE Main 2022
Grade 11
Question:
The eccentricity of the hyperbola $\frac{x^2}{3} - y^2 = 1$ is:
(1) $2$
(2) $\sqrt{2}$
(3) $\frac{2}{\sqrt{3}}$
(4) $\frac{2\sqrt{3}}{3}$
Step-by-Step Solution
Key Concept: $a^2 = 3, b^2 = 1; c^2 = a^2 + b^2 = 4; e = c/a = 2/\sqrt{3}$.
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: (3)