Question:

<div class="solution"><p><strong>Key Idea:</strong> Factor denominator: <span class="math-inline">$r^2+3r+3=1+(r+1)(r+2)$</span>.</p><p><strong>Step 1:</strong> <span class="math-block">$$T_r=\tan^{-1}\!\frac{(r+2)-(r+1)}{1+(r+2)(r+1)}=\tan^{-1}(r+2)-\tan^{-1}(r+1)$$</span></p><p><strong>Step 2:</strong> Telescoping sum: <span class="math-inline">$\lim_{n\to\infty}[\tan^{-1}(n+2)-\tan^{-1}(1)]=\pi/2-\pi/4=\pi/4$</span>.</p><p><strong>Answer: (B) <span class="math-inline">$\pi/4$</span></strong></p><div class="trap-box"><strong>Trap:</strong> Miscounting the starting index — the first term at r=0 must be verified.</div><div class="key-concept"><strong>Key Concept:</strong> tan⁻¹ telescoping sum — factor denominator as 1+product of consecutive terms</div></div>