The value of $\sin^{-1}(\sin 10)$ (angle in radians) is:
Step-by-Step Solution
Key Concept: Range of $\sin^{-1}$ is $[-\pi/2, \pi/2]$. Write $10 = 3\pi + (10 - 3\pi)$, use $\sin(3\pi + \theta) = -\sin \theta$, then apply $\sin^{-1}$ to a negative value.
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Correct Answer: (3)