Basic Maths and Logarithm
Logarithmic Equations
JEE Advanced (IIT-JEE 2002)
Grade 11

Question:

The number of positive integers satisfying $x + \log_{10}(2^x + 1) = x \log_{10} 5 + \log_{10} 6$ is:
(1) $0$
(2) $1$
(3) $2$
(4) $\infty$

Step-by-Step Solution

Key Concept: Rewrite: $x(1-\log_{10} 5)+\log_{10}(2^x+1) = \log_{10} 6$. Since $1-\log_{10} 5 = \log_{10} 2$: $\log_{10}(2^x(2^x+1)) = \log_{10} 6$. So $(2^x)^2 + 2^x - 6 = 0 \Rightarrow 2^x = 2$ (reject $2^x = -3$), giving $x = 1$.
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Correct Answer: (2)

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