<p>A bag contains 10 balls: 4 red and 6 blue. Two balls are drawn without replacement. The probability that both are red is</p>
Step-by-Step Solution
Key Concept: P(both red) = (4/10) \times (3/9) = 12/90 = 2/15.
<p>4 red, 6 blue, 10 total.</p><p>$P(\text{both red}) = \dfrac{4}{10} \times \dfrac{3}{9} = \dfrac{12}{90} = \dfrac{2}{15}$</p><p>Equivalently: $\dfrac{\binom{4}{2}}{\binom{10}{2}} = \dfrac{6}{45} = \dfrac{2}{15}$ ✓</p>
Correct Answer: A