<p>A lot contains 50 defective and 50 non-defective bolts. Two bolts are drawn successively without replacement. The probability that the second bolt is defective given that the first is non-defective is</p>
Step-by-Step Solution
Key Concept: After drawing 1 non-defective bolt, 99 bolts remain: 50 defective, 49 non-defective. P = 50/99.
<p>Given first bolt is non-defective: 99 bolts remain, of which 50 are defective.</p><p>$P(\text{2nd defective} \mid \text{1st non-defective}) = \dfrac{50}{99}$</p>
Correct Answer: A