Probability
Classical Probability
IIT-JEE 1998
Grade 12

Question:

A box contains 100 tickets numbered 1 to 100. Two tickets are chosen at random. The probability that the numbers on them are not consecutive is:
(1) $\frac{49}{50}$
(2) $\frac{1}{50}$
(3) $\frac{99}{100}$
(4) $\frac{1}{2}$

Step-by-Step Solution

Key Concept: First find the total number of ways to choose 2 tickets from 100, and separately count how many of these pairs are consecutive (such as (1, 2), (2, 3), ...).
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: (1)

Master Probability with Mathbee

Practice this topic under real exam conditions with strict timers, or ask our AI Mentor to explain the concepts step-by-step.

Start Practicing for Free