Sequence and Series
Special Series
JEE Main 2019
Grade 11

Question:

The sum $1 + \frac{1^3 + 2^3}{1 + 2} + \frac{1^3 + 2^3 + 3^3}{1 + 2 + 3} + \dots$ up to 15 terms is:
(1) $620$
(2) $660$
(3) $680$
(4) $720$

Step-by-Step Solution

Key Concept: The $n$-th term is $\frac{[n(n+1)/2]^2}{n(n+1)/2} = \frac{n(n + 1)}{2}$. Sum $\sum_{n=1}^{15} \frac{n(n+1)}{2}$ using standard formulas.
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: (3)

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