Statistics
Variance
IIT-JEE 2003
Grade 11

Question:

The variance of the first 10 natural numbers is:
(1) $\frac{33}{4}$
(2) $\frac{99}{4}$
(3) $\frac{11}{4}$
(4) $\frac{33}{2}$

Step-by-Step Solution

Key Concept: Use the standard result that the variance of the first $n$ natural numbers is $\frac{n^2 - 1}{12}$, and substitute $n = 10$.
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: (1)

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