Vector Algebra
Grade 12

Question:

<p>Let \(\vec{a},\vec{b}\) be two non-zero non-collinear vectors. Then \(|\vec{a}\times\vec{b}|\) equals</p>
\(|\vec{a}||\vec{b}|\sin\theta\)
\(|\vec{a}||\vec{b}|\cos\theta\)
\(|\vec{a}||\vec{b}|\)
\(|\vec{a}||\vec{b}|\sin\theta\) with \(\vec{a}\times\vec{b}\perp\vec{a}\) and \(\vec{a}\times\vec{b}\perp\vec{b}\)

Step-by-Step Solution

Key Concept: Cross product magnitude is |a||b|sin\theta AND the result is perpendicular to both -- all of these properties together define the cross product.
By definition, \(\vec{a}\times\vec{b}\) is a vector with: <ul>Magnitude \(|\vec{a}||\vec{b}|\sin\theta\) Direction perpendicular to both \(\vec{a}\) and \(\vec{b}\)</ul> Option D states both the magnitude formula AND the perpendicularity -- making it the most complete and correct statement. Answer: (D)
Correct Answer: D

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