Polynomials
Grade Class 10

Question:

<p><strong>Assertion (A): </strong>A quadratic polynomial, sum of whose zeroes is&nbsp;8&nbsp;and their product&nbsp;&nbsp;is&nbsp;12&nbsp;is&nbsp;x<sup>2&nbsp;</sup>&minus; 20x + 96<br /> <strong>Reason (R):</strong>&nbsp;If&nbsp;<span class="math-tex">\(\alpha\)</span>&nbsp;and&nbsp;<span class="math-tex">\(\beta\)</span>&nbsp;be the zeroes of the polynomial&nbsp;f(x), then polynomial is given by f(x) = x<sup>2</sup> -&nbsp;<span class="math-tex">\((\alpha+\beta) x\)</span>&nbsp;+&nbsp;<span class="math-tex">\(\alpha \beta\)</span></p>
<p style="display:inline">Both A and R are true and R is the correct explanation of A.</p>
<p style="display:inline">Both A and R are true but R is not the correct explanation of A.</p>
<p style="display:inline">A is true but R is false.</p>
<p style="display:inline">A is false but R is true.</p>

Step-by-Step Solution

Key Concept: A quadratic polynomial is constructed by substituting the given sum and product of zeroes into the standard form $x^2 - (sum\ of\ zeroes)x + (product\ of\ zeroes)$.
<p>Reason is correct. If <span class="math-tex">\(\alpha\)</span> and <span class="math-tex">\(\beta\)</span> be the zeroes of the required polynomial f(x),<br /> then&nbsp;<span class="math-tex">\((\alpha+\beta)\)</span>&nbsp;= 8 and&nbsp;<span class="math-tex">\(\alpha \beta\)</span>&nbsp;= 12<br /> <span class="math-tex">\(\therefore\)</span>&nbsp;f(x) = x<sup>2</sup> -&nbsp;<span class="math-tex">\((\alpha+\beta) \mathrm{x}+\alpha \beta\)</span><br /> <span class="math-tex">\(\Rightarrow\)</span>&nbsp;f(x) = x<sup>2</sup> - 8x + 12<br /> So, Assertion is not correct</p>
Correct Answer: D

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