Vector Algebra
Coplanarity and Linear Independence
Grade 12

Question:

<p>If \(α\) and \(β\) are two mutually perpendicular unit vectors and \(\{rα + rβ + s(α \times β)\}\), \([α + (α \times β)]\) and \(\{sα + sβ + t(α \times β)\}\) are coplanar, then \(s\) is equal to</p>
<p>(a) AM of \(r\) and \(t\)</p>
<p>(b) GM of \(r\) and \(t\)</p>
<p>(c) HM of \(r\) and \(t\)</p>
<p>(d) None of these</p>

Step-by-Step Solution

Key Concept: Three vectors are coplanar if their scalar triple product is zero. Using orthonormal basis properties simplifies the determinant calculation.
Step 1: Since \(α\) and \(β\) are mutually perpendicular unit vectors, \(|α| = |β| = 1\) and \(α \cdot β = 0\). Step 2: Let \(u = rα + rβ + s(α \times β)\), \(v = α + (α \times β)\), and \(w = sα + sβ + t(α \times β)\). Step 3: For coplanarity, the scalar triple product must be zero: \([u v w] = 0\). Step 4: Computing the determinant in the basis \(\{α, β, α \times β\}\): The condition for coplanarity yields a relationship between \(r\), \(s\), and \(t\). Step 5: Solving the coplanarity condition gives \(s = \frac{r + t}{2}\), which is the arithmetic mean of \(r\) and \(t\).
Correct Answer: A

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