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Arithmetic Progressions

CH05 Question Bank

CBSE_CH05_QUESTION_BANK

Grade 10

Question:

The $11$th term from the end of the AP $10, 7, 4, \ldots, -62$ is:

$-25$
$-28$
$-32$
$-35$

Step-by-Step Solution

Key Concept: The $n$th term from the end is given by $l-(n-1)d$, using the same common difference $d$ as the original AP.

Here $l=-62$ and $d=-3$. [0.5 Mark]

$11$th term from the end $=l-(11-1)d=-62-(10)(-3)=-62+30=-32$. [0.5 Mark]

Correct Answer: $-32$

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