Trigonometry
Equation
MMTS_Full_Test_08
Grade 12

Question:

The general solution of $\cos 2\theta\cos\left(\dfrac{\theta}{2}\right)=\cos\left(\dfrac{3\theta}{2}\right)$ is
$(4n+1)\pi/2$
$(2n+1)\pi/2$
$(2n-1)\pi/2$
$n\pi/2$

Step-by-Step Solution

Key Concept: Use product-to-sum: $\cos 2\theta\cos(\theta/2)=\frac{1}{2}[\cos(5\theta/2)+\cos(3\theta/2)]$
$\cos(5\theta/2)=\cos(3\theta/2)\Rightarrow 5\theta/2=\pm3\theta/2+2n\pi$. Case 1: $\theta=n\pi$; Case 2: $4\theta=2n\pi\Rightarrow\theta=n\pi/2$. General: $\theta=n\pi/2$.
Correct Answer: 3

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