Polynomials
Grade Class 10
Question:
<p>The sum of zeroes of the polynomial <span class="math-tex">\(\sqrt 2\)</span> x<sup>2</sup> - 17 are given as:</p>
<p style="display:inline">0</p>
<p style="display:inline"><span class="math-tex">\(\frac{17 \sqrt{2}}{2}\)</span></p>
<p style="display:inline">1</p>
<p style="display:inline"><span class="math-tex">\(-\frac{17 \sqrt{2}}{2}\)</span></p>
Step-by-Step Solution
Key Concept: The sum of the zeroes of a quadratic polynomial is calculated as the ratio of the coefficient of the linear term (x) to the coefficient of the leading term (x²).
<p>Given; P(x) = <span class="math-tex">$\sqrt 2$</span> x<sup>2</sup> - 17<br />
Sum of zeroes = <span class="math-tex">$\frac {\text {coeff of x}}{\text {coeff of}\space x^2}$</span><br />
= 0</p>
Correct Answer: A