Limits, Continuity & Differentiability
Methods of Differentiation
Grade 12

Question:

<p>If $y = \ln\\!\left\{\dfrac{x + \sqrt{a^2 + x^2}}{a}\right\}$, then the value of $\dfrac{dy}{dx}$ is:</p>
<p>$\sqrt{a^2-x^2}$</p>
<p>$\sqrt{a^2+x^2}$</p>
<p>$\dfrac{1}{\sqrt{a^2+x^2}}$</p>
<p>$x\sqrt{a^2+x^2}$</p>

Step-by-Step Solution

Key Concept: General
<b>Standard Form — Inverse Hyperbolic</b><br>This is the inverse sinh form: $y = \sinh^{-1}\\!\left(\frac{x}{a}\right)$.<br>Direct differentiation: $\frac{dy}{dx} = \frac{d}{dx}\left[\ln\\!\left(x+\sqrt{a^2+x^2}\right) - \ln a\right]$<br>$= \frac{1}{x+\sqrt{a^2+x^2}} \cdot \left(1 + \frac{x}{\sqrt{a^2+x^2}}\right) = \frac{1}{\sqrt{a^2+x^2}}$<br><b>Key concept:</b> $\frac{d}{dx}\sinh^{-1}\\!\left(\frac{x}{a}\right) = \frac{1}{\sqrt{a^2+x^2}}$<br><b>Trap:</b> Students compute the full quotient derivative unnecessarily; recognise the standard form.
Correct Answer: C

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