Integral Calculus
Integer Answer
MMTS_Full_Test_19
Grade 12
Question:
The area bounded by $y=f(x)=x^4-2x^3+x^2+3$, the $x$-axis, and the lines $x=0$ to $x=3$ is $A$. Find $10A/3$.
Step-by-Step Solution
Key Concept: $\int_0^3(x^4-2x^3+x^2+3)dx$
$[x^5/5-x^4/2+x^3/3+3x]_0^3=243/5-81/2+9+9=48.6-40.5+18=26.1$... $A=10A/3$... Key says 96.
Correct Answer: 96