Polynomials
CBSE 2026 Board Exam Set 1 (Code 30/7/1)
CBSE_BOARD_PYQ_2026_30_7_1
Grade 10
Question:
[Section A]
The zeroes of the quadratic polynomial $x^2 - x - 6$ are:
(A) $-3, 2$
(B) $3, 2$
(C) $3, -2$
(D) $-3, -2$
Step-by-Step Solution
Key Concept: Factorize $x^2 - x - 6 = (x - 3)(x + 2) = 0$.
Sol. (C) $3, -2$. [1.0 Mark]
Correct Answer: (C) $3, -2$
Confused by the solution? Ask the AI to explain a specific step, tell you where you went wrong, or break down the key trap in this question.