Trigonometry & Inverse Trigonometry
Trigonometric Identities
Grade 11
Question:
<p>The value of <span class="math">\frac{\sin x - \cos x}{\sin^3 x}\) is equal to:</p>
<p>(a) \(\cosec^2 x(1 - \cot x)\)</p>
<p>(b) \(1 - \cot x + \cot^2 x - \cot^3 x\)</p>
<p>(c) \(\cosec^2 x - \cot x - \cot^3 x\)</p>
<p>(d) \(\frac{1 - \cot x}{\sin^2 x}\)</p>
Step-by-Step Solution
Key Concept: Rewrite the expression in terms of trigonometric functions and manipulate algebraically to match one or more given forms.
<p>All options are equivalent forms of the given expression.</p>
Correct Answer: a, b, c, d