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Coordinate Geometry

CBSE 2026 Board Exam Set 1 (Code 30/7/1)

CBSE_BOARD_PYQ_2026_30_7_1

Grade 10

Question:

[Section A]

The distance of the point $P(-2, 2)$ from the origin is:

(A) $2$
(B) $4$
(C) $2\sqrt{2}$
(D) $8$

Step-by-Step Solution

Key Concept: Distance $= \sqrt{(-2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$.

Sol. (D) $2\sqrt{2}$. [1.0 Mark]

Correct Answer: (D) $2\sqrt{2}$

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