Algebra
Permutations & Combinations
MMTS_Full_Test_22
Grade 12
Question:
The number of ways of distributing 10 different books among 4 students (S1 to S4) such that S1 gets 2 books, S2 gets 3 books, S3 gets 2 books and S4 gets 3 books is
$\dfrac{10!}{2!3!2!3!}$
$\dfrac{10!}{(2!)^2(3!)^2}$
$10!$
None of these
Step-by-Step Solution
Key Concept: Number of ways $=\binom{10}{2}\binom{8}{3}\binom{5}{2}\binom{3}{3}=\frac{10!}{2!3!2!3!}$
$\frac{10!}{2!3!2!3!}$. Answer: 1.
Correct Answer: 3