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Calculus
Differentiation, Chain Rule
jee_main_2026_april_5_shift_1
Grade 12

Question:

The derivative of y = sin(2x² + 3x) at x = 0 is:
A. 0
B. 1
C. 2
D. 3

Step-by-Step Solution

Key Concept: Use chain rule: d/dx sin(u) = cos u × du/dx.
Step 1: u = 2x² + 3x. dy/dx = cos(2x² + 3x) × (4x + 3). Step 2: At x = 0, dy/dx = cos 0 × 3 = 3.
Correct Answer: D
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