Functions
Zeros of x²sin(π/x²) — counting solutions
MJAT_TS7_P2
Grade 12

Question:

Let $f:\mathbb{R}\to\mathbb{R}$ be defined by $f(x)=x^2\sin\!\left(\dfrac{\pi}{x^2}\right)$ for $x\neq 0$, $f(0)=0$. Then which of the following is TRUE?
A) $f(x)=0$ has infinitely many solutions in $\left[10^{-10},\infty\right)$
B) $f(x)=0$ has no solutions in $\left[\dfrac{1}{\pi},\infty\right)$
C) The set of solutions of $f(x)=0$ in $\left(0,10^{-10}\right)$ is finite
D) $f(x)=0$ has more than 25 solutions in $\left(\dfrac{1}{\pi^2},\dfrac{1}{\pi}\right)$

Step-by-Step Solution

Key Concept: $f(x)=0\Rightarrow\sin(\pi/x^2)=0\Rightarrow\pi/x^2=n\pi\Rightarrow x=1/\sqrt{n}$ for $n\in\mathbb{N}$.
Answer: **D**.
Correct Answer: D

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