Matrices & Determinants
System of Linear Equations
Grade Class 12

Question:

The number of real values &lambda;, such that the system of linear equations<br>2x - 3y + 5z = 9<br>x + 3y - z = -18<br>3x - y + (&lambda;<sup>2</sup> - |&lambda;|)z = 16<br>has no solution, is :-
(1) 0
(2) 1
(3) 2
(4) 4

Step-by-Step Solution

Key Concept: A system of linear equations has no solution if the determinant of the coefficient matrix is zero and the system is inconsistent (i.e., the augmented matrix has a row of the form [0 0 0 | k] where k is non-zero).
The coefficient matrix is A = [[2, -3, 5], [1, 3, -1], [3, -1, &lambda;<sup>2</sup> - |&lambda;|]]. The determinant |A| = 2(3(&lambda;<sup>2</sup> - |&lambda;|) - 1) + 3(1(&lambda;<sup>2</sup> - |&lambda;|) + 3) + 5(-1 - 9) = 6&lambda;<sup>2</sup> - 6|&lambda;| - 2 + 3&lambda;<sup>2</sup> - 3|&lambda;| + 9 - 50 = 9&lambda;<sup>2</sup> - 9|&lambda;| - 43. Setting |A| = 0 gives 9&lambda;<sup>2</sup> - 9|&lambda;| - 43 = 0. Let t = |&lambda;| &ge; 0, then 9t<sup>2</sup> - 9t - 43 = 0. The roots are t = (9 &plusmn; &radic;(81 - 4(9)(-43))) / 18 = (9 &plusmn; &radic;(81 + 1548)) / 18 = (9 &plusmn; &radic;1629) / 18. Since &radic;1629 &gt; 9, one root is positive and one is negative. Since t = |&lambda;| &ge; 0, only the positive root is valid, giving two values for &lambda; (&plusmn;t). Checking consistency for these values shows the system is inconsistent.
Correct Answer: (3)

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