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Coordinate Geometry
Ellipse, Eccentricity
jee_main_2026_april_5_shift_1
Grade 12

Question:

The eccentricity of the ellipse x²/25 + y²/9 = 1 is e. Find the value of 5e.
A. 2
B. 3
C. 4
D. 5

Step-by-Step Solution

Key Concept: Ellipse eccentricity: e = √(1 - b²/a²).
Step 1: a² = 25, b² = 9. Step 2: e = √(1 - 9/25) = √(16/25) = 4/5. Step 3: 5e = 4.
Correct Answer: C
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