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Coordinate Geometry
Ellipse, Eccentricity
jee_main_2026_jan_22_shift_1
Grade None

Question:

The eccentricity of the ellipse x²/16 + y²/7 = 1 is:
A. 1/2
B. 3/4
C. 4/5
D. 5/6

Step-by-Step Solution

Key Concept: Ellipse eccentricity: e = √(1 - b²/a²).
Step 1: a² = 16, b² = 7. Step 2: e = √(1 - 7/16) = √(9/16) = 3/4.
Correct Answer: B
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