Sets, Relations & Functions
Relation on Product Set — Count via Common Value
nta_pyq_2026_jan
Grade 11

Question:

Let $R$ be a relation defined on the set $\{1,2,3,4\}\times\{1,2,3,4\}$ by $R=\{((a,b),(c,d)):2a+3b=3c+4d\}$. Then the number of elements in $R$ is
18
6
15
12

Step-by-Step Solution

Key Concept: Need $2a+3b=3c+4d=k$. For each valid $k$, count pairs $(a,b)$ with $2a+3b=k$ and $(c,d)$ with $3c+4d=k$, multiply.
12 elements.
Correct Answer: 4

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