Introduction to Trigonometry
CH08 Question Bank
CBSE_CH08_QUESTION_BANK
Grade 10
Question:
Simplify: $\dfrac{\sin^2 45^\circ + \cos^2 45^\circ}{\tan^2 45^\circ}$.
Step-by-Step Solution
Key Concept: Substitute standard values.
Numerator $=\sin^245^\circ+\cos^245^\circ=1$ (by the Pythagorean identity). [1.0 Mark]
Denominator $=\tan^245^\circ=1^2=1$. So the expression $=\dfrac11=1$. [1.0 Mark]
Correct Answer:
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