Straight Lines
General
Grade 11
Question:
Given the points A(<span class="math-inline">0</span>,<span class="math-inline">4</span>) and B(<span class="math-inline">0</span>,<span class="math-inline">-4</span>), the equation of the locus of the point P such that <span class="math-inline">|AP - BP| = 6</span> is -
<span class="math-inline">9x² - 7y² + 63 = 0</span>
<span class="math-inline">9x² - 7y² - 63 = 0</span>
<span class="math-inline">7x² - 9y² + 63 = 0</span>
<span class="math-inline">7x² - 9y² - 63 = 0</span>
Step-by-Step Solution
Key Concept: General
x² + y² - 4x - 6y - 12 = 0
Correct Answer: 2