Limits, Continuity & Differentiability
General
Grade 12
Question:
<p>The value of limx→0
| cos(sin 3x)|−1
x2
is:</p>
<p>−9/2</p>
<p>−3/2</p>
<p>3/2</p>
<p>9/2</p>
Step-by-Step Solution
Key Concept: General
<p>Near x</p> = 0, cos(sin 3x) is positive, so absolute value can be removed. Limit = \lim_{x \to 0} cos(sin 3x)-1 (sin 3x)2 \cdot sin2 3x x2 = (-1/2) \cdot 9 = -9/2.
Correct Answer: 1