Question:
<p>The normal at a point P on the parabola y<sup>2</sup> = 8x meet the x-axis in G. If S is the focus and the triangle SPG is equilateral then the abscissa of the point P is</p>
<p style="display:inline">3</p>
<p style="display:inline">6</p>
<p style="display:inline"><span class="math-tex">\(2 \sqrt{3}\)</span></p>
<p style="display:inline">2/3</p>
Step-by-Step Solution
Key Concept: Utilize the property that the triangle formed by the focus S, point P, and normal intersection G is isosceles (SP=SG), then apply the equilateral condition PG=SP to find the abscissa.
<p>6</p>
Correct Answer: B