Matrices & Determinants
Properties of determinants
Grade Class 12

Question:

If x, y, z are distinct digits (0 &le; x, y, z &le; 9) & the minimum possible value of <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced open="|"><mtable><mtr><mtd><mi>z</mi></mtd><mtd><mn>9</mn><mi>y</mi></mtd><mtd><mi>x</mi></mtd></mtr><mtr><mtd><mi>z</mi></mtd><mtd><mi>y</mi></mtd><mtd><mn>9</mn><mi>x</mi></mtd></mtr><mtr><mtd><mn>9</mn><mi>z</mi></mtd><mtd><mi>y</mi></mtd><mtd><mi>x</mi></mtd></mtr></mtable></mfenced></math> is &lambda; then <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mi>&lambda;</mi><mn>83700</mn></mfrac></math> is (where 9x, 9y & 9z are two digits number)
9

Step-by-Step Solution

Key Concept: The determinant can be expanded by expressing the two-digit numbers as 90+x, 90+y, 90+z. The expression simplifies to a form involving (x-y), (y-z), and (z-x). Since x, y, z are distinct digits, we minimize the absolute value of the resulting expression.
The determinant is <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>&#x2223;</mo><mtable><mtr><mtd><mi>z</mi></mtd><mtd><mn>90</mn><mo>+</mo><mi>y</mi></mtd><mtd><mi>x</mi></mtd></mtr><mtr><mtd><mi>z</mi></mtd><mtd><mi>y</mi></mtd><mtd><mn>90</mn><mo>+</mo><mi>x</mi></mtd></mtr><mtr><mtd><mn>90</mn><mo>+</mo><mi>z</mi></mtd><mtd><mi>y</mi></mtd><mtd><mi>x</mi></mtd></mtr></mtable><mo>&#x2223;</mo></math>. Performing row operations R1 -> R1 - R2 and R2 -> R2 - R3, we get <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>&#x2223;</mo><mtable><mtr><mtd><mn>0</mn></mtd><mtd><mn>90</mn></mtd><mtd><mo>-</mo><mn>90</mn></mtd></mtr><mtr><mtd><mo>-</mo><mn>90</mn></mtd><mtd><mn>0</mn></mtd><mtd><mn>90</mn></mtd></mtr><mtr><mtd><mn>90</mn><mo>+</mo><mi>z</mi></mtd><mtd><mi>y</mi></mtd><mtd><mi>x</mi></mtd></mtr></mtable><mo>&#x2223;</mo></math>. Expanding this gives 8100(x+y+z+90). To minimize the absolute value, we choose distinct digits x, y, z such that the sum is minimized. The minimum sum of three distinct digits is 0+1+2=3. Thus, the minimum value is 8100(3+90) = 8100 * 93 = 753300. Dividing by 83700 gives 9.
Correct Answer: 9

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