Trigonometry & Inverse Trigonometry
cosec 10° − √3 sec 10°
nta_pyq_2026_jan
Grade 11
Question:
The value of $\text{cosec}10°-\sqrt{3}\sec10°$ is equal to:
Step-by-Step Solution
Key Concept: $\text{cosec}10°-\sqrt{3}\sec10°=\dfrac{\cos10°-\sqrt{3}\sin10°}{\sin10°\cos10°}$. Numerator $=2\left(\tfrac{1}{2}\cos10°-\tfrac{\sqrt{3}}{2}\sin10°\right)=2\cos70°=2\sin20°$.
$4$.
Correct Answer: 4