Matrices & Determinants
Determinant expansion and polynomial coefficients
Grade 12
Question:
<p><strong>For Problems 10–12</strong><br>\[f(x) = \begin{vmatrix} x+c_1 & x+a & x+a \\ x+b & x+c_2 & x+a \\ x+b & x+b & x+c_3 \end{vmatrix}\] and \(g(x) = (c_1 - x)(c_2 - x)(c_3 - x)\)</p><p>Coefficient of \(x\) in \(f(x)\) is</p>
<p>\(\dfrac{g(a)-f(b)}{b-a}\)</p>
<p>\(\dfrac{g(-a)-g(-b)}{b-a}\)</p>
<p>\(\dfrac{g(a)-g(b)}{b-a}\)</p>
<p>none of these</p>
Step-by-Step Solution
Key Concept: The determinant f(x) is a cubic polynomial in x. Expand it systematically and identify the coefficient of x by tracking linear terms that arise from products of entries.
<p><strong>Step 1:</strong> Recognize that $f(x)$ is a polynomial of degree at most 3 in $x$. We need the coefficient of $x^1$.</p>
<p><strong>Step 2:</strong> Use column operations to simplify. Subtract column 2 from column 1 and column 3:</p>
<p>$C_1 \to C_1 - C_2$, $C_3 \to C_3 - C_2$</p>
<p><strong>Step 3:</strong> After subtraction:</p>
$$\begin{vmatrix} c_1 - b & x+a & c_1-c_2 \\ -a & x+c_2 & c_2-a \\ -a & x+b & c_3-a \end{vmatrix}$$
<p><strong>Step 4:</strong> The determinant has the form: (constant terms) $+$ (coefficient of $x$) $\cdot x$ $+$ higher order terms.</p>
<p><strong>Step 5:</strong> Expanding along column 2 (which isolates the $x$ terms):</p>
<p>$f(x) = (x+a) \cdot M_1 + (x+c_2) \cdot M_2 + (x+b) \cdot M_3$ where $M_i$ are $2 \times 2$ minors.</p>
<p><strong>Step 6:</strong> The coefficient of $x$ equals the sum of all $2 \times 2$ minors obtained by removing row $i$ and column 2.</p>
<p><strong>Step 7:</strong> By careful expansion (or using the relationship with $g(x)$): coefficient of $x$ in $f(x)$ is $$\frac{g(a)-g(b)}{b-a}$$</p>
<p>$\therefore$ Answer: C</p>
Correct Answer: C