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Real Numbers
CBSE 2026 Board Exam Set 3 (Code 30/1/3)
CBSE_BOARD_PYQ_2026_30_1_3
Grade 10

Question:

[Section B]

Prove that $\sqrt{5}$ is an irrational number.

Step-by-Step Solution

Key Concept: Proof by contradiction using coprimes and divisibility.
Let $\sqrt{5} = p/q$ where $p, q$ are coprime integers ($q
eq 0$). Then $5q^2 = p^2 \Rightarrow p^2$ is divisible by $5 \Rightarrow p$ is divisible by $5$. Let $p = 5k$, then $25k^2 = 5q^2 \Rightarrow q^2 = 5k^2 \Rightarrow q$ is divisible by $5$. This contradicts coprimality. Hence $\sqrt{5}$ is irrational. [2.0 Marks]

Correct Answer: Proof completed.
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