Question:

Let $(\alpha,\beta)$ be circumcenter of the triangle formed by vertices $(1,5)$, $(-3,4)$ and $(10,-31)$. Then value of $8\alpha-2\beta$ equals

(A) 55

(B) $-2$

(D) none of these

Step-by-Step Solution

Key Concept: Set up two perpendicular bisector equations and solve for $\alpha,\beta$.

$8\alpha-2\beta=55$.

Correct Answer: (A) 55