Limits, Continuity & Differentiability
General
Grade 12

Question:

<p>If f(x) is an odd linear polynomial with f(1) = 1, then limx→0 2f(tan x)−2f(sin x) x2f(sin x) is:</p>
1
ln 2
1/2 ln 2
cos 2

Step-by-Step Solution

Key Concept: General
<p>f(x) is odd linear</p> =\Rightarrow f(x) = cx. f(1) = 1 =\Rightarrow c = 1 =\Rightarrow f(x) = x. Limit = \lim_{x \to 0} 2tan x-2sin x x2 sin x = lim 2sin x(2tan x-sin x-1) x2 sin x . Using at-1 t \to ln a: lim 1 \cdot (tan x-sin x) ln 2 x3 = lim (x3/2) ln 2 x3 = 1 2 ln 2.
Correct Answer: 3

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