Trigonometry
Properties of Triangle
MMTS_Full_Test_13
Grade 12

Question:

In a $\triangle ABC$, if $a=2x$, $b=2y$ and $C=120°$, the area of triangle is
$xy$
$2xy\sin60°$
$\sqrt{3}xy$
$2\sqrt{3}xy$

Step-by-Step Solution

Key Concept: Area $=\frac{1}{2}ab\sin C=\frac{1}{2}\cdot 2x\cdot 2y\cdot\sin120°$
Area $=\frac{1}{2}\cdot4xy\cdot\frac{\sqrt{3}}{2}=\sqrt{3}xy$.
Correct Answer: 2

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