Matrices & Determinants
General
Grade 12

Question:

Let $A$ be a matrix of order $2 \times 2$ such that $A^2 = O$. Then $A^2 - (a + d)A + (ad - bc)I$ is equal to
$I$
$O$
$-I$
none of these

Step-by-Step Solution

Key Concept: General
Let $A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}$ <br/> $\Rightarrow A^2 - (a + d)A + (ad - bc)I$ <br/> $= \begin{bmatrix} a & b \\ c & d \end{bmatrix} \begin{bmatrix} a & b \\ c & d \end{bmatrix} - (a + d) \begin{bmatrix} a & b \\ c & d \end{bmatrix} + (ad - bc) \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$ <br/> $= \begin{bmatrix} a^2 + bc & ab + bd \\ ac + cd & bc + d^2 \end{bmatrix} - \begin{bmatrix} a^2 + ad & ab + bd \\ ac + cd & ad + d^2 \end{bmatrix} + \begin{bmatrix} ad - bc & 0 \\ 0 & ad - bc \end{bmatrix} = O$
Correct Answer: B

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