Binomial Theorem
Binomial Theorem
star_batch_jee_advanced_2025
Grade 11

Question:

Let $x = (5\sqrt{5} + 8)^{2n+1}$, $n \in \mathbb{N}$, then :
$[x]$ is even
$[x]$ is odd
$x\{x\} = (11)^{2n+1}$
$x\{x\} = (13)^{2n+1}$

Step-by-Step Solution

Key Concept: The locus is determined by the argument condition which specifies the angle that $z - (1+i)$ makes with the positive real axis in different regions.
Step 1: Identify the mathematical property and reference point. The solution describes a property related to a complex number, specifically its argument, with respect to a fixed reference point in the complex plane. This reference point is given as $(1,1)$. Step 2: Define the argument for the first condition. For points where the real part $x$ is less than or equal to $2$, the argument of the complex number relative to point $(1,1)$ is specified as $\frac{3\pi}{4}$. $$ \text{Argument} = \frac{3\pi}{4} \quad \text{for } x \leq 2 $$ Step 3: Define the argument for the second condition. For points where the real part $x$ is greater than $2$, the argument of the complex number relative to point $(1,1)$ is specified as $-\frac{\pi}{4}$. $$ \text{Argument} = -\frac{\pi}{4} \quad \text{for } x > 2 $$ Step 4: Summarize the geometric interpretation. Combining these two conditions, the described argument represents a locus of points. Since the argument is constant for specific regions, this locus consists of two rays. Both rays originate from the reference point $(1,1)$. One ray extends for $x \leq 2$ at an angle of $\frac{3\pi}{4}$, and the other ray extends for $x > 2$ at an angle of $-\frac{\pi}{4}$.
Correct Answer: I need to analyze the expression $x = (5\sqrt{5} + 8)^{2n+1}$ where $n \in \mathbb{N}$. Let me consider the conjugate expression and use the binomial theorem approach. Let $y = (5\sqrt{5} - 8)^{2n+1}$

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