The compound statement $(\sim p \vee q) \wedge (\sim p \wedge \sim q)$ is
Step-by-Step Solution
Key Concept: $(\sim p\wedge\sim q)$ implies $\sim q$; combined with $(\sim p\vee q)$: if $q=F$, need $\sim p=T$; check all rows.
When $p=F,q=F$: $(T\vee F)\wedge(T\wedge T)=T\wedge T=T$. When $p=F,q=T$: $(T\vee T)\wedge(T\wedge F)=T\wedge F=F$. So not always T or always F. Neither tautology nor contradiction.
Correct Answer: C