Permutations & Combinations
Selection with Constraints
Grade 11

Question:

<p>In how many ways can the letters of the word DIPESH be placed in the squares of the adjoining figure so that no row remains empty?</p>

Step-by-Step Solution

Key Concept: Use complementary counting: subtract the configurations where at least one row is empty from total configurations.
<p><strong>Step 1:</strong> The word DIPESH has 6 letters. There are 8 squares in the figure arranged in rows.</p><p><strong>Step 2:</strong> We need to select 6 squares from 8 to place the letters such that no row remains empty.</p><p><strong>Step 3:</strong> Total ways to select 6 squares from 8: $$\binom{8}{6} = \binom{8}{2} = \frac{8 \cdot 7}{2} = 28$$</p><p><strong>Step 4:</strong> Exclude cases where either the top row or bottom row has no X (letter):</p><p>Cases to exclude = 2 (either top row empty or bottom row empty)</p><p><strong>Step 5:</strong> Required number of ways = 28 - 2 = 26</p>
Correct Answer: 26

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