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Coordinate Geometry
CBSE 2026 Board Exam Set 1 (Code 30/1/1)
CBSE_BOARD_PYQ_2026_30_1_1
Grade 10

Question:

[Section A]

The distance of the point $P(-6, 8)$ from the origin is:

(A) $8$
(B) $2\sqrt{7}$
(C) $10$
(D) $6$

Step-by-Step Solution

Key Concept: Distance $= \sqrt{(-6)^2 + 8^2} = \sqrt{36+64} = 10$.
Sol. (C) $10$. [1.0 Mark]

Correct Answer: (C) $10$
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