Permutations & Combinations
Grade 11
Question:
<p>Some identical balls are arranged in rows to form an equilateral triangle. The first row consists of one ball, the second row consists of two balls and so on. If 99 more identical balls are added to the total number of balls used in forming the equilateral triangle, then all these balls can be arranged in a square whose each side contains exactly 2 balls less than the number of balls each side of the triangle contains. Then, the number of balls used to form the equilateral triangle is</p>
<p style="display:inline">190</p>
<p style="display:inline">157</p>
<p style="display:inline">225</p>
<p style="display:inline">262</p>
Step-by-Step Solution
Key Concept: Equate the sum of the first n natural numbers, representing the triangular arrangement, to the square of the adjusted side length to solve for n.
<p>Let there are n balls used to form the sides of equilateral triangle. According to the question, we have<br />
<span class="math-tex">$\frac{n(n+1)}{2}$</span> + 99 = (n - 2)<sup>2</sup><br />
<span class="math-tex">$\Rightarrow$</span> n<sup>2</sup> + n + 198 = 2 [n<sup>2</sup> - 4n + 4]<br />
<span class="math-tex">$\Rightarrow$</span> n<sup>2</sup> - 9n - 190 = 0<br />
<span class="math-tex">$\Rightarrow$</span> n<sup>2</sup> - 19n + 10n - 190 = 0<br />
<span class="math-tex">$\Rightarrow$</span> (n - 19) (n + 10) = 0<br />
<span class="math-tex">$\Rightarrow$</span> n = 19, - 10<br />
<span class="math-tex">$\Rightarrow$</span> n = 19 [<span class="math-tex">$\because$</span> number of balls n > 0]<br />
Now, number of balls used to form an equilateral triangle is <span class="math-tex">$\frac{n(n+1)}{2}$</span><br />
<span class="math-tex">$=\frac{19 \times 20}{2}=190$</span></p>
Correct Answer: A