Limits, Continuity & Differentiability
General
Grade 12

Question:

<p>limx→1+ (1−|x|+sin |1−x|) sin( π 2 [1−x]) |1−x|[1−x] is equal to: (1) −1 (2) 1 (3) D.N.E (4) 0</p>
-1
1
D.N.E
0

Step-by-Step Solution

Key Concept: General
<p><strong>1</strong>: As x \to 1+, |x| = x, |1 -x| = x -1, and [1 -x] = -1.</p><p><strong>2</strong>: Substitue: (1-x+sin(x-1)) sin(-\pi/2)</p> (x-1)(-1) = sin(x-1)-(x-1) x-1 .<p><strong>3</strong>: Let t = x -1. \lim_{t \to 0} sin t-t</p> t = \lim_{t \to 0} sin t t -1  = 1 -1 = 0.
Correct Answer: (4)

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