Basic Mathematics & Logarithm
Inequality involving logarithm and sign analysis
Grade 11

Question:

<p>Solve the inequality: <span>\( \dfrac{x(\pi^x - 7^x)(x-1)(x-3)}{(x-6)\log_{10}(x-4)} > 0 \)</span>. Find the solution set.</p>
<p>\( (4,5) \cup (6,\infty) \)</p>
<p>\( (0,1) \cup (4,5) \)</p>
<p>\( (1,3) \cup (5,6) \)</p>
<p>\( (3,4) \cup (6,\infty) \)</p>

Step-by-Step Solution

Key Concept: Analyze the sign of each factor separately, paying careful attention to domain restrictions (logarithm requires argument > 0, denominator ≠ 0) and where each factor changes sign. The solution requires determining intervals where the overall expression is positive.
<p><strong>Step 1: Determine Domain</strong></p><p>For log₁₀(x-4) to exist: x > 4</p><p>Also (x-6) ≠ 0, so x ≠ 6</p><p>Domain: (4, 6) ∪ (6, ∞)</p><p><strong>Step 2: Analyze Each Factor</strong></p><p>• <strong>x:</strong> Zero at x = 0 (outside domain), positive for x > 4</p><p>• <strong>(π^x - 7^x):</strong> Since π < 7, we have π^x < 7^x for all x. So this factor is always negative</p><p>• <strong>(x-1):</strong> Positive for x > 4</p><p>• <strong>(x-3):</strong> Positive for x > 4</p><p>• <strong>(x-6):</strong> Negative on (4,6), positive on (6,∞)</p><p>• <strong>log₁₀(x-4):</strong> Zero at x = 5; negative on (4,5); positive on (5,∞)</p><p><strong>Step 3: Sign Table on Domain (4,6) ∪ (6,∞)</strong></p><p>On (4, 5):</p><p>Numerator: (+)(−)(+)(+) = (−)</p><p>Denominator: (−)(−) = (+)</p><p>Quotient: (−)/(+) = (−) ✗</p><p>On (5, 6):</p><p>Numerator: (+)(−)(+)(+) = (−)</p><p>Denominator: (−)(+) = (−)</p><p>Quotient: (−)/(−) = (+) ✓</p><p>On (6, ∞):</p><p>Numerator: (+)(−)(+)(+) = (−)</p><p>Denominator: (+)(+) = (+)</p><p>Quotient: (−)/(+) = (−) ✗</p><p><strong>∴ Answer: (5, 6)</strong></p>
Correct Answer: A

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