Question:

If $f:[-1,1]\to[0,2]$ defined by $f(x)=1+x$, then $f^{-1}$ is

$f^{-1}(x)=x-1$

$f^{-1}(x)=1-x$

$f^{-1}(x)=1+x$

$f^{-1}$ does not exist

Step-by-Step Solution

Key Concept: $f(x)=1+x$ is bijection; inverse is $x-1$

$f^{-1}(x)=x-1$.

Correct Answer: 1